วัฏจักรแฮมิลตันเป็นเส้นทางแฮมิลตันที่มีขอบ (ในกราฟ) จากจุดยอดสุดท้ายถึงจุดสุดยอดแรกของเส้นทางแฮมิลตัน มันอยู่ในกราฟที่ไม่มีทิศทางเป็นเส้นทางที่เข้าชมแต่ละจุดยอดของกราฟเพียงครั้งเดียว
หน้าที่และวัตถุประสงค์
Begin 1. function isSafe() is used to check for whether it is adjacent to the previously added vertex and already not added. 2. function hamiltonianCycle() solves the hamiltonian problem. 3. function hamCycle() uses hamiltonianCycle() to solve the hamiltonian problem. It returns false if there is no Hamiltonian Cycle possible, otherwise return true and prints the path. End
ตัวอย่าง
#include <iostream> #include <cstdio> #include <cstdlib> #define N 5 using namespace std; void displaytheSolution(int path[]); bool isSafe(int n, bool g[N][N], int path[], int pos) { if (g [path[pos-1]][n] == 0) return false; for (int i = 0; i < pos; i++) if (path[i] == n) return false; return true; } bool hamiltonianCycle(bool g[N][N], int path[], int pos) { //If all vertices are included in Hamiltonian Cycle if (pos == N) { if (g[ path[pos-1] ][ path[0] ] == 1) return true; else return false; } for (int n = 1; n < N; n++) { if (isSafe(n, g, path, pos)) //Check if this vertex can be added to Hamiltonian Cycle { path[pos] = n; //recur to construct rest of the path if (hamiltonianCycle (g, path, pos+1) == true) return true; path[pos] = -1; //remove vertex if it doesn’t lead to the solution } } return false; } bool hamCycle(bool g[N][N]) { int *path = new int[N]; for (int i = 0; i < N; i++) path[i] = -1; //put vertex 0 as the first vertex in the path. If there is a Hamiltonian Cycle, then the path can be started from any point //of the cycle as the graph is undirected path[0] = 0; if (hamiltonianCycle(g, path, 1) == false) { cout<<"\nCycle does not exist"<<endl; return false; } displaytheSolution(path); return true; } void displaytheSolution(int p[]) { cout<<"Cycle Exists:"; cout<<" Following is one Hamiltonian Cycle \n"<<endl; for (int i = 0; i < N; i++) cout<<p[i]<<" "; cout<< p[0]<<endl; } int main() { bool g[N][N] = {{0, 1, 0, 1, 1}, {0, 0, 1, 1, 0}, {0, 1, 0, 1, 1}, {1, 1, 1, 0, 1}, {0, 1, 1, 0, 0}, }; hamCycle(g); return 0; }
ผลลัพธ์
Cycle Exists: Following is one Hamiltonian Cycle 0 4 1 2 3 0