กำหนด k sorted linked lists ต้อง merge เป็น 1 sorted linked list ใช้ heap (priority queue)
ตัวอย่าง: [1,4,5], [1,3,4], [2,6] → [1,1,2,3,4,4,5,6]
ขั้นตอนการแก้ปัญหา
- สร้าง Min Heap
- insert head ของทุก list เข้า heap
- วน extract min: นำ node ที่เล็กที่สุดต่อเข้ากับผลลัพธ์ แล้ว push node.next เข้า heap (ถ้ามี)
- จน heap ว่าง
ตัวอย่างโค้ด
class ListNode:
def __init__(self, data, next=None):
self.val = data
self.next = next
def make_list(elements):
head = ListNode(elements[0])
for element in elements[1:]:
ptr = head
while ptr.next:
ptr = ptr.next
ptr.next = ListNode(element)
return head
def print_list(head):
ptr = head
print('[', end="")
while ptr:
print(ptr.val, end=", ")
ptr = ptr.next
print(']')
class Heap:
def __init__(self):
self.arr = []
def getVal(self, i):
return self.arr[i].val
def parent(self, i):
return (i-1)//2
def left(self, i):
return 2*i + 1
def right(self, i):
return 2*i + 2
def insert(self, value):
self.arr.append(value)
n = len(self.arr)-1
i = n
while i != 0 and self.arr[i].val < self.arr[self.parent(i)].val:
self.arr[i], self.arr[self.parent(i)] = self.arr[self.parent(i)], self.arr[i]
i = self.parent(i)
def heapify(self, i):
left = self.left(i)
right = self.right(i)
smallest = i
n = len(self.arr)
if left < n and self.getVal(left) < self.getVal(smallest):
smallest = left
if right < n and self.getVal(right) < self.getVal(smallest):
smallest = right
if smallest != i:
self.arr[i], self.arr[smallest] = self.arr[smallest], self.arr[i]
self.heapify(smallest)
def extractMin(self):
n = len(self.arr)
if n == 0:
return '#'
if n == 1:
temp = self.arr[0]
self.arr.pop()
return temp
root = self.arr[0]
self.arr[0] = self.arr[-1]
self.arr.pop()
self.heapify(0)
return root
class Solution(object):
def mergeKLists(self, lists):
heap = Heap()
for i in lists:
if i:
heap.insert(i)
res = None
res_next = None
while True:
temp = heap.extractMin()
if temp == '#':
return res
if not res:
res = temp
res_next = temp
temp = temp.next
if temp:
heap.insert(temp)
res.next = None
else:
res_next.next = temp
temp = temp.next
res_next = res_next.next
if temp:
heap.insert(temp)
res_next.next = None
ob = Solution()
lists = [[1,4,5],[1,3,4],[2,6]]
lls = []
for ll in lists:
l = make_list(ll)
lls.append(l)
print_list(ob.mergeKLists(lls))
อินพุต
[[1,4,5],[1,3,4],[2,6]]
เอาต์พุต
[1, 1, 2, 3, 4, 4, 5, 6, ]