ฟังก์ชัน numpy.vdot() คำนวณผลคูณจุดของเวกเตอร์ 1 มิติ จัดการกับจำนวนเชิงซ้อนโดยใช้ complex conjugate ของอาร์กิวเมนต์แรก
ขั้นตอน
import numpy as np
arr1 = np.array([2+3j, 5+6j])
arr2 = np.array([9+10j, 11+12j])
print("Array1...\n", arr1)
print("\nArray2...\n", arr2)
print("\nDimensions of Array1...\n", arr1.ndim)
print("\nDimensions of Array2...\n", arr2.ndim)
print("\nShape of Array1...\n", arr1.shape)
print("\nShape of Array2...\n", arr2.shape)
print("\nResult...\n", np.vdot(arr1, arr2))
ตัวอย่างโค้ดสมบูรณ์
import numpy as np
arr1 = np.array([2+3j, 5+6j])
arr2 = np.array([9+10j, 11+12j])
print("Array1...\n", arr1)
print("\nArray2...\n", arr2)
print("\nDimensions of Array1...\n", arr1.ndim)
print("\nDimensions of Array2...\n", arr2.ndim)
print("\nShape of Array1...\n", arr1.shape)
print("\nShape of Array2...\n", arr2.shape)
print("\nResult...\n", np.vdot(arr1, arr2))
ผลลัพธ์
Array1... [2.+3.j 5.+6.j] Array2... [ 9.+10.j 11.+12.j] Dimensions of Array1... 1 Dimensions of Array2... 1 Shape of Array1... (2,) Shape of Array2... (2,) Result... (175-13j)
